(8x-3)(x^2-4)=0

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Solution for (8x-3)(x^2-4)=0 equation: 


Simplifying
(8x + -3)(x2 + -4) = 0

Reorder the terms:
(-3 + 8x)(x2 + -4) = 0

Reorder the terms:
(-3 + 8x)(-4 + x2) = 0

Multiply (-3 + 8x) * (-4 + x2)
(-3(-4 + x2) + 8x * (-4 + x2)) = 0
((-4 * -3 + x2 * -3) + 8x * (-4 + x2)) = 0
((12 + -3x2) + 8x * (-4 + x2)) = 0
(12 + -3x2 + (-4 * 8x + x2 * 8x)) = 0
(12 + -3x2 + (-32x + 8x3)) = 0

Reorder the terms:
(12 + -32x + -3x2 + 8x3) = 0
(12 + -32x + -3x2 + 8x3) = 0

Solving
12 + -32x + -3x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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